Work and Energy

Understanding energy transformations and the work-energy theorem

Introduction to Work and Energy

Work and energy are fundamental concepts in physics that provide an alternative approach to analyzing motion. Instead of directly using Newton's laws and kinematics, we can often solve problems more easily by considering the work done on an object and the resulting changes in its energy. This approach is particularly powerful for complex systems and provides deep insights into the conservation laws that govern our universe.

Work

Work is the energy transferred to or from an object when a force is applied to it over a distance. Mathematically, work is the dot product of the force vector and the displacement vector.

Work Formula
\[W = \vec{F} \cdot \vec{d} = Fd \cos \theta\]
Where:
  • \(W\) = work (in joules, J)
  • \(\vec{F}\) = force vector (in newtons, N)
  • \(\vec{d}\) = displacement vector (in meters, m)
  • \(\theta\) = angle between force and displacement vectors

Key points about work:

  • Work is a scalar quantity (not a vector)
  • Work can be positive, negative, or zero
  • Work is positive when the force component is in the same direction as the displacement
  • Work is negative when the force component opposes the displacement
  • Work is zero when the force is perpendicular to the displacement (\(\cos 90° = 0\))
Example 1: Work Calculation

A person pushes a 50 kg crate with a force of 200 N at an angle of 30° below the horizontal, moving it 5 meters across a floor. Calculate the work done by the pushing force.

\[W = Fd \cos \theta = 200 \text{ N} \times 5 \text{ m} \times \cos(30°)\]

\[W = 200 \times 5 \times 0.866 = 866 \text{ J}\]

Kinetic Energy

Kinetic energy is the energy an object possesses due to its motion. It depends on both mass and velocity.

Kinetic Energy Formula
\[KE = \frac{1}{2}mv^2\]
Where:

    Kinetic Energy:

    KE = ½mv²

    Where:

    • KE = kinetic energy (in joules, J)
    • m = mass (in kilograms, kg)
    • v = speed (in meters per second, m/s)

    Example: Calculate the kinetic energy of a 1500 kg car traveling at 20 m/s.

    KE = ½mv² = ½ × 1500 kg × (20 m/s)² = 750 kg × 400 m²/s² = 300,000 J = 300 kJ

    Work-Energy Theorem

    The work-energy theorem states that the net work done on an object equals the change in its kinetic energy.

    Work-Energy Theorem:

    Wnet = ΔKE = KEfinal - KEinitial = ½m(vf² - vi²)

    Where:

    • Wnet = net work done on the object
    • ΔKE = change in kinetic energy
    • vi = initial velocity
    • vf = final velocity

    Example: A 2 kg ball initially moving at 5 m/s speeds up to 8 m/s. How much work was done on the ball?

    Wnet = ΔKE = ½m(vf² - vi²) = ½ × 2 kg × ((8 m/s)² - (5 m/s)²) = 1 kg × (64 m²/s² - 25 m²/s²) = 39 J

    Potential Energy

    Potential energy is stored energy that an object has due to its position or condition. Two common types are gravitational potential energy and elastic potential energy.

    Gravitational Potential Energy

    This is the energy an object possesses due to its height above a reference level.

    Gravitational Potential Energy:

    PEg = mgh

    Where:

    • PEg = gravitational potential energy (in joules, J)
    • m = mass (in kilograms, kg)
    • g = acceleration due to gravity (9.8 m/s²)
    • h = height above the reference level (in meters, m)

    Example: A 5 kg object is lifted 2 meters above the ground. Calculate its gravitational potential energy relative to the ground.

    PEg = mgh = 5 kg × 9.8 m/s² × 2 m = 98 J

    Elastic Potential Energy

    This is the energy stored in elastic materials when they are stretched or compressed.

    Elastic Potential Energy:

    PEe = ½kx²

    Where:

    • PEe = elastic potential energy (in joules, J)
    • k = spring constant (in newtons per meter, N/m)
    • x = displacement from equilibrium position (in meters, m)

    Example: A spring with a spring constant of 400 N/m is compressed by 0.1 meters. Calculate the elastic potential energy stored in the spring.

    PEe = ½kx² = ½ × 400 N/m × (0.1 m)² = 200 N/m × 0.01 m² = 2 J

    Conservation of Energy

    The law of conservation of energy states that energy cannot be created or destroyed but can only be transferred or converted from one form to another. In a closed system, the total energy remains constant.

    Conservation of Mechanical Energy:

    KEi + PEi = KEf + PEf

    or

    Etotal = constant

    Where:

    • KE = kinetic energy
    • PE = potential energy
    • i = initial state
    • f = final state

    In the presence of non-conservative forces like friction, the mechanical energy is not conserved, but the total energy (including heat and other forms) is still conserved.

    Example: A 2 kg ball is dropped from a height of 5 meters. Neglecting air resistance, what is its speed just before it hits the ground?

    Using conservation of energy:

    KEi + PEi = KEf + PEf

    0 + mgh = ½mv² + 0

    mgh = ½mv²

    gh = ½v²

    v² = 2gh

    v = √(2gh) = √(2 × 9.8 m/s² × 5 m) = √98 m²/s² ≈ 9.9 m/s

    Power

    Power is the rate at which work is done or energy is transferred. It tells us how quickly energy is being used or produced.

    Power:

    P = W/t = Fv

    Where:

    • P = power (in watts, W, or joules per second, J/s)
    • W = work (in joules, J)
    • t = time (in seconds, s)
    • F = force (in newtons, N)
    • v = velocity (in meters per second, m/s)

    Example: A 60 kg person climbs a staircase that is 5 meters high in 10 seconds. Calculate the power output.

    Work done = mgh = 60 kg × 9.8 m/s² × 5 m = 2940 J

    Power = W/t = 2940 J / 10 s = 294 W

    Applications of Work and Energy

    Understanding work and energy is essential for many applications:

    • Energy generation and transformation (power plants, solar panels)
    • Transportation (efficiency of vehicles, regenerative braking)
    • Sports (optimizing performance, understanding collisions)
    • Engineering design (elevators, roller coasters, springs)
    • Environmental science (energy resources, conservation)

    Practice Problems

    Coming soon! Check back for practice problems and detailed solutions.